Question on: JAMB Mathematics - 2024
Find the equation of a line perpendicular to the line 4y = 7x + 3 which passes through (-3, 1)
A
7y + 4x + 5 = 0
B
7y - 4x - 5 = 0
C
3y - 5x + 2 = 0
D
3y + 5x - 2 = 0
Ask EduPadi AI for a detailed answer
Correct Option: A
Rewrite the equation:
\[ y = \frac{7}{4}x + \frac{3}{4} \]
Slope = \(\frac{7}{4}\)
Perpendicular slope:
\[ -\frac{4}{7} \]
Using point-slope form for point (-3, 1):
\[ y - 1 = -\frac{4}{7}(x + 3) \]
Simplifying:
\[ y = -\frac{4}{7}x - \frac{5}{7} \]
Multiply by 7:
\[ 4x + 7y + 5 = 0 \]
Final Answer: 4x + 7y + 5 = 0
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